A) A, B
B) B, C
C) C, D
D) A, D
Correct Answer: C
Solution :
Position isomer of ethylidene chloride is ethylene dichloride \[\left( \underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,-\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\, \right)\]and propyl formate\[(HCOOC{{H}_{2}}C{{H}_{2}}C{{H}_{3}})\]is the metamer of ethyl acetate.You need to login to perform this action.
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