A) \[y-x+1=0\]
B) \[y-x+2=0\]
C) \[y-x-1=0\]
D) \[y-x-2=0\]
Correct Answer: C
Solution :
The equation of line perpendicular to \[x+y+1=0\]is\[x-y+\lambda =0\] Since, it passes through the point (1, 2). \[\therefore \] \[1-2+\lambda =0\] \[\Rightarrow \] \[-1+\lambda =0\] \[\Rightarrow \] \[\lambda =1\] Hence, equation of perpendicular line is \[x-y+1=0\] or \[y-x-1=0\]You need to login to perform this action.
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