A) (15, 10)
B) \[\left( \frac{3}{2},5 \right)\]
C) (10, 15)
D) \[(-4,\text{ }5)\]
Correct Answer: C
Solution :
Given, points A (8,5),\[B(-7,-5)\]and\[C(-5,5)\]are the vertices of a parallelogram. Let fourth vertex is\[D(x,\text{ }y)\]. We know that, diagonals of a parallelogram \[\therefore \]intersect each other at mid point \[\therefore \] \[\frac{8-5}{2}=\frac{x-7}{2}\] \[\Rightarrow \] \[3=x-7\] \[\Rightarrow \] \[x=10\] and \[\frac{5+5}{2}=\frac{y-5}{2}\] \[\Rightarrow \] \[10=y-5\] \[\Rightarrow \] \[y=15\] \[\therefore \]Coordinates of D are (10, 15).You need to login to perform this action.
You will be redirected in
3 sec