A) \[{{x}^{2}}+{{y}^{2}}-x+y-4=0\]
B) \[{{x}^{2}}+{{y}^{2}}+x+y-4=0\]
C) \[{{x}^{2}}+{{y}^{2}}-x-y-4=0\]
D) None of the above
Correct Answer: C
Solution :
\[A(-1,2)\]and\[B(2,-1)\]are the end points of diameter of circle. Hence, equation of circle AB as diameter is \[(x+1)(x-2)+(y-2)(y+1)=0\] \[\Rightarrow \] \[{{x}^{2}}-2x+x-2+{{y}^{2}}+y-2y-2=0\] \[\Rightarrow \] \[{{x}^{2}}+{{y}^{2}}+x-y-4=0\]You need to login to perform this action.
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