A) \[1\,sq\,unit\]
B) \[3\,sq\,unit\]
C) \[2\,sq\,unit\]
D) \[\frac{3}{2}\,sq\,unit\]
Correct Answer: D
Solution :
Required area\[=\int_{1}^{2}{y\,dx}=\int_{1}^{2}{\frac{3}{{{x}^{2}}}}dx\] \[=3\left[ -\frac{1}{x} \right]_{1}^{2}\] \[=3\left[ -\frac{1}{2}+\frac{1}{1} \right]\] \[=3.\left( \frac{1}{2} \right)\] \[=\frac{3}{2}\]sq unitsYou need to login to perform this action.
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