A) 2
B) \[\frac{1}{2}\]
C) 0
D) None of these
Correct Answer: B
Solution :
\[x=a{{t}^{2}},y=2at\] \[\frac{dx}{dt}=2at,\frac{dy}{dt}=2a\] \[\therefore \] \[\frac{dy}{dx}=\frac{dy/dt}{dx/dt}=\frac{2a}{2at}=\frac{1}{t}\] At \[t=2,\frac{dy}{dx}=\frac{1}{2}\]You need to login to perform this action.
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