A) 1 : 1
B) 1 : 2
C) 3 : 1
D) 1 : 4
Correct Answer: B
Solution :
\[E=k{{a}^{2}}\Rightarrow E\propto {{a}^{2}}\] Or \[\frac{a_{1}^{2}}{a_{2}^{2}}=\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{1}{4}\] Or \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{1}{2}\]You need to login to perform this action.
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