A) \[25{}^\circ C\]
B) \[250{}^\circ C\]
C) 250 K
D) \[2500{}^\circ C\]
Correct Answer: B
Solution :
\[p\propto T\] \[\frac{p}{p+\left( \frac{0.4}{100} \right)p}=\frac{T}{T+1}\] \[T=250{}^\circ C\]You need to login to perform this action.
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