RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    The pH of solution which obtains on adding 10 mL 0.2 M\[NaOH\]solution with 10 mL 0.1 M \[{{H}_{2}}S{{O}_{4}}\]will be

    A)  zero               

    B)  2.0

    C)  4.0                

    D)  7.0

    Correct Answer: D

    Solution :

     \[10\text{ }mL\text{ }0.2\text{ }M\text{ }NaOH=10\text{ }mL\text{ }0.1\text{ }M\text{ }{{H}_{2}}S{{O}_{4}}\] \[10\times 0.2\]equivalent\[\equiv 10\times 0.2\]equivalent The solution will neutral hence its pHwill be 7.


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