A) \[HCHO\]
B) \[C{{H}_{3}}COC{{H}_{3}}\]
C) \[C{{H}_{3}}CHO\]
D) \[C{{H}_{3}}C{{H}_{2}}OH\]
Correct Answer: C
Solution :
Acetaldehyde give both iodoform and Fehling test. \[C{{H}_{3}}CHO+{{I}_{2}}+4NaOH\xrightarrow[test]{Iodoform}\] \[\underset{yellow\text{ }ppt}{\mathop{CH{{I}_{3}}}}\,+HCOONa+3{{H}_{2}}O+3NaI\] \[C{{H}_{3}}CHO+\underset{blue}{\mathop{2CuO}}\,\xrightarrow[Fehiling\,test]{\Delta }\] \[C{{H}_{3}}COOH+\underset{red\text{ }ppt}{\mathop{C{{u}_{2}}O}}\,\]
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