A) +3
B) \[-3\]
C) +6
D) \[-6\]
Correct Answer: C
Solution :
Let the oxidation number of Cr in\[{{R}_{2}}Cr{{O}_{4}}\]is\[x\]. \[2+(1)+x+4(-2)=0\] \[2+x-8=0\] \[x=8-2\] \[=6\]You need to login to perform this action.
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