A) 6
B) 7
C) 8
D) 11
Correct Answer: A
Solution :
Given, \[{{\left| \begin{matrix} 4 & 1 \\ 2 & 1 \\ \end{matrix} \right|}^{2}}=\left| \begin{matrix} 3 & 2 \\ 1 & x \\ \end{matrix} \right|-\left| \begin{matrix} x & 3 \\ -2 & 1 \\ \end{matrix} \right|\] \[\Rightarrow \] \[{{(4-2)}^{2}}=(3x-2)-(x+6)\] \[\Rightarrow \] \[4=2x-8\] \[\Rightarrow \] \[2x=12\] \[\Rightarrow \] \[x=6\]You need to login to perform this action.
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