A) \[-1\]
B) \[1\]
C) 0
D) \[\infty \]
Correct Answer: C
Solution :
\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{{{x}^{2}}\sin (1/x)-x}{1-|x|}\] Let\[x=1/t,\]then \[\underset{t\to 0}{\mathop{\lim }}\,\frac{\frac{1}{{{t}^{2}}}\sin t-\frac{1}{t}}{1-\frac{1}{t}}\] \[=\underset{t\to 0}{\mathop{\lim }}\,\frac{\frac{\sin t}{t}-1}{t-1}=0\]You need to login to perform this action.
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