A) \[\frac{1}{3}\]
B) \[\frac{2}{3}\]
C) \[1\]
D) \[\frac{8}{3}\]
Correct Answer: D
Solution :
Given, equation of line is\[3x+y=3\] \[\Rightarrow \] \[3x+y-3=0\] Equation of its perpendicular line is \[x-3y+\lambda =0\] and it passes through the point\[(-2,2)\] \[\therefore \] \[-2-3\times 2+\lambda =0\] \[\Rightarrow \] \[\lambda =8\] \[\therefore \]Equation is \[x-3y+8=0\] For the intercept on y-axis, \[x=0\] Then, \[3y=8\] \[\Rightarrow \] \[y=\frac{8}{3}\]You need to login to perform this action.
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