A) 0.5 mm
B) 2 mm
C) 1.1 mm
D) 1.75 mm
Correct Answer: B
Solution :
According to question \[mg=2\pi rT\] \[\Rightarrow \] \[r=\frac{mg}{2\pi T}\] \[=\frac{72\times {{10}^{-6}}}{2\times 3.14\times 0.06}\] \[=2\text{ }mm\]You need to login to perform this action.
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