A) 0.16 A
B) 0.32 A
C) 3.2 A
D) 1.6 A
Correct Answer: B
Solution :
\[I=\frac{1}{R}\frac{d\phi }{dt}\] \[=\frac{1}{R}\times \frac{AdB}{dt}\] \[I=\frac{1}{2\times {{10}^{-3}}}\times 16\times {{10}^{-4}}\times 0.4\] \[I=0.32\,A\]You need to login to perform this action.
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