A) \[+q\]
B) \[-q\]
C) \[+2q\]
D) \[-2g\]
Correct Answer: B
Solution :
Here \[{{F}_{AB}}+{{F}_{CB}}=0\] \[\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{4{{q}^{2}}}{{{l}^{2}}}+\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{Qq}{{{l}^{2}}/4}=0\] \[\Rightarrow \] \[4Qq=-4{{q}^{2}}\] \[\Rightarrow \] \[Q=-q\]You need to login to perform this action.
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