RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    The average emf induced in a coil in which current changes from 2 A to 4 A in 0.05 s is 8 V. What is the self inductance of the coil?

    A)  0.5 H             

    B)  0.35 H

    C)  0.2 H             

    D)  2 mH

    Correct Answer: C

    Solution :

     Self inductance \[L=-\frac{e}{(\Delta I/\Delta t)}=-\frac{8}{(4-2)/0.08}\] \[=-0.2\,H\]


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