A) L/2
B) L
C) 3L/2
D) 2L
Correct Answer: D
Solution :
\[{{n}_{closed}}=\frac{v}{4L}\] \[{{n}_{open}}=\frac{v}{2L'}\] According to question \[{{n}_{closed}}={{n}_{open}}\] \[\Rightarrow \] \[L'=2L\]You need to login to perform this action.
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