A) 205 Hz
B) 210 Hz
C) 220 Hz
D) 195 Hz
Correct Answer: A
Solution :
Suppose the frequency of tuning fork is n, the frequency of wire will be\[n+5\] According to law of length \[{{n}_{1}}{{l}_{1}}={{n}_{2}}{{l}_{2}}\] Or \[(n+5)\times 20=(n-5)\times 2l\] \[20n+100=21n+105\] \[n=205Hz\]You need to login to perform this action.
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