A) \[3A\]
B) \[1.1A\]
C) \[2.1A\]
D) \[1.5A~\]
Correct Answer: B
Solution :
\[I={{B}_{H}}\times \frac{2R\tan \theta }{N{{\mu }_{0}}}\] \[=4\times {{10}^{-5}}\times \frac{2\times 0.1\times \tan 60{}^\circ }{10\times 4\pi \times {{10}^{-7}}}\] \[=1.1A\]You need to login to perform this action.
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