A second pendulum is taken in a satellite moving at a height of 2R from the earth's surface. At that position the time period (in second) of pendulum will be
A) 0
B) 2
C) 4
D)\[\infty \]
Correct Answer:
D
Solution :
Acceleration due to gravity in satellite\[(g)=0\] Time period \[(T)=2\pi \sqrt{\frac{l}{g}}=\infty \]