A) \[mgH\]
B) \[\sqrt{2gH}\]
C) \[2gH\]
D) zero
Correct Answer: B
Solution :
The potential energy of pendulum at point C will be equal to kinetic energy at point B \[\frac{1}{2}mV_{B}^{2}=mgH\] \[{{v}_{B}}=\sqrt{2gH}\]You need to login to perform this action.
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