A) 1 : 4
B) 1 : 2
C) 1 : 8
D) 1 : 3
Correct Answer: C
Solution :
\[H=\frac{KA\Delta \theta }{l}\] or \[H\propto \frac{{{r}^{2}}}{l}\] so, \[\frac{{{H}_{1}}}{{{H}_{2}}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{2}}\left( \frac{{{I}_{2}}}{{{I}_{1}}} \right)\] \[={{\left( \frac{1}{2} \right)}^{2}}\left( \frac{1}{2} \right)\] \[=\frac{1}{8}\] \[\Rightarrow \] \[{{H}_{1}}:{{H}_{2}}=1:8\]You need to login to perform this action.
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