A) \[-\frac{Q}{2}\]
B) \[-\frac{Q}{4}\]
C) \[+\frac{Q}{4}\]
D) \[+\frac{Q}{2}\]
Correct Answer: B
Solution :
In equilibrium position \[{{F}_{AB}}+{{F}_{AC}}=0\] \[\Rightarrow \] \[\frac{1}{4\pi {{\varepsilon }_{0}}}\left[ \frac{Qq}{{{d}^{2}}/4}+\frac{{{Q}^{2}}}{{{d}^{2}}} \right]=0\] \[\Rightarrow \] \[\frac{4Qq}{{{d}^{2}}}=-\frac{{{Q}^{2}}}{{{d}^{2}}}\] \[\therefore \] \[q=-\frac{Q}{4}\]You need to login to perform this action.
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