A) 4
B) 2
C) 1/2
D) 1
Correct Answer: B
Solution :
\[{{W}_{1}}=MB(\cos 0{}^\circ -\cos 60{}^\circ )\] \[=MB\left( 1-\frac{1}{2} \right)=\frac{MB}{2}\] \[{{W}_{2}}=MB(\cos 0{}^\circ -\cos 90{}^\circ )=MB\] Given: \[{{W}_{2}}=n{{W}_{1}}\] \[\therefore \] \[n=2\]You need to login to perform this action.
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