A) 0.02 s
B) 0.2 s
C) 0.4 s
D) 0.04 s
Correct Answer: A
Solution :
Time of exposure\[\propto {{(f\,number)}^{2}}\]\[\Rightarrow \]\[\frac{{{t}_{2}}}{{{t}_{1}}}={{\left[ \frac{5.6}{2.8} \right]}^{2}}=4\] \[{{t}_{2}}=4{{t}_{1}}=4\times \frac{1}{200}=\frac{1}{50}s=0.02\,s\]You need to login to perform this action.
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