A) 2 Pa
B) 8 Pa
C) 16 Pa
D) 10 Pa
Correct Answer: B
Solution :
The excess pressure\[=\frac{4T}{R}\] \[=\frac{4\times 0.03}{\frac{30}{2}\times {{10}^{-3}}}\] \[=8\text{ }Pa\]You need to login to perform this action.
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