A) \[0.17\overset{o}{\mathop{\text{A}}}\,\]
B) \[1.06\overset{o}{\mathop{\text{A}}}\,\]
C) \[0.53\overset{o}{\mathop{\text{A}}}\,\]
D) \[0.265\overset{o}{\mathop{\text{A}}}\,\]
Correct Answer: A
Solution :
Atomic radius\[=\frac{0.53{{n}^{2}}}{Z}\overset{o}{\mathop{\text{A}}}\,\] where \[n=\]number of orbital \[Z=\]atomic number radius or\[L{{i}^{2+}}\]ion\[=\frac{0.53\times 1}{3}\overset{o}{\mathop{\text{A}}}\,\] \[=0.176\overset{o}{\mathop{\text{A}}}\,\]You need to login to perform this action.
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