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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2006

  • question_answer
    An electron of mass m when accelerated through a potential difference V has de-Broglie wavelength\[\lambda \]. The de- Broglie wavelength associated with a proton of mass M accelerated through the same potenial difference will be

    A)  \[\lambda \sqrt{\frac{m}{M}}\]

    B)  \[\frac{\lambda M}{m}\]

    C)  \[\frac{\lambda m}{M}\]

    D)  \[\lambda \sqrt{\frac{M}{m}}\]

    Correct Answer: A

    Solution :

     \[\lambda =\frac{h}{\sqrt{2mE}}\] \[\Rightarrow \] \[\lambda \propto \frac{1}{\sqrt{m}}\] \[(E=same)\] \[\frac{{{\lambda }_{p}}}{\lambda }=\sqrt{\frac{m}{M}}\] \[\Rightarrow \] \[{{\lambda }_{p}}=\lambda \sqrt{\frac{m}{M}}\]


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