A) \[25{{s}^{-1}}\]
B) \[80{{s}^{-1}}\]
C) \[625{{s}^{-1}}\]
D) \[20{{s}^{-1}}\]
Correct Answer: B
Solution :
Given: \[{{t}_{1/2}}=36\text{ }min=1800s\] No. of half year \[n=\frac{2\times 60\times 60}{1800}\] \[n=4\] \[{{A}_{0}}={{(2)}^{n}}.N={{2}^{4}}\times 5\] \[{{A}_{0}}=80{{s}^{-1}}\]You need to login to perform this action.
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