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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2006

  • question_answer
    The angle of prism is\[30{}^\circ \]. A ray passes through the prism and suffers a deviation of\[30{}^\circ \]. If the angle of incidence is\[60{}^\circ ,\]then angle of emergence is

    A)  \[0{}^\circ \]               

    B)  \[30{}^\circ \]

    C)  \[60{}^\circ \]               

    D)  \[90{}^\circ \]

    Correct Answer: A

    Solution :

     Angle of prism \[A=30{}^\circ \] Incident angle \[i=60{}^\circ \] Deviation angle\[\delta =30{}^\circ \] \[\delta =e+i-A\] \[e=A+\delta -i\] \[=30{}^\circ +30{}^\circ -60{}^\circ \] \[e=0\]


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