A) (1, 2)
B) (2, 2)
C) (2, 12)
D) (12, 12)
Correct Answer: B
Solution :
Given, line is\[3x+4y-24=0\]. It cuts the\[x-\]axis at A (8,0) and y-axis at B(0,6). In\[\Delta OAB,\] \[a=6,b=8\] and \[C=\sqrt{{{6}^{2}}+{{8}^{2}}}=\sqrt{100}=10\] \[\therefore \]Coordinates of incentre are \[\left( \frac{a{{x}_{1}}+b{{x}_{2}}+c{{x}_{3}}}{a+b+c},\frac{a{{y}_{1}}+b{{y}_{2}}+c{{y}_{3}}}{a+b+c} \right)\] \[=\left( \frac{6\times 8+8\times 0+10\times 0}{6+8+10},\frac{6\times 0+8\times 6+10\times 0}{6+8+10} \right)\] \[=\left( \frac{48}{24},\frac{48}{24} \right)=(2,2)\]You need to login to perform this action.
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