A) 1
B) 2
C) 3
D) 4
Correct Answer: A
Solution :
Required area, \[A=\int_{1-e}^{0}{{{\log }_{e}}(x+e)dx}\] Put \[x+e=t\Rightarrow dx=dt\] \[\therefore \] \[A=\int_{1}^{e}{{{\log }_{e}}t\,dt}\] \[=[t\log t-t]_{1}^{e}\] \[=(e-e-0+1)\] \[=1\]You need to login to perform this action.
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