A) \[{{t}_{1/2}}=\frac{0.693}{k}\]
B) \[N={{N}_{0}}{{e}^{-kt}}\]
C) \[\frac{1}{N}-\frac{1}{{{N}_{0}}}=In\,k{{t}_{1/2}}\]
D) None of these
Correct Answer: C
Solution :
Rate of radioactive decay is directly proportional to the total number of atoms present in it. \[-\frac{dN}{dt}=kN\] where, \[k=\]decay constant \[{{N}_{t}}={{N}_{0}}{{e}^{-kt}}\] In \[\frac{{{N}_{0}}}{N}=kT\] and \[{{t}_{1/2}}=\frac{0.693}{k}\]You need to login to perform this action.
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