A) \[b+c\]
B) \[a+b\]
C) \[a+b+c\]
D) \[c+a\]
Correct Answer: B
Solution :
\[\angle C=\frac{\pi }{2},\]we know that\[\frac{c}{\sin C}=2R\] \[\Rightarrow \] \[c=2R\] \[\left[ \because \sin \frac{\pi }{2}=1 \right]\] and \[\tan \frac{C}{2}=\frac{r}{s-c}\] \[\Rightarrow \] \[\tan \frac{\pi }{4}=\frac{r}{s-c}\] \[\Rightarrow \] \[r=s-c=\frac{a+b+c}{2}-c\] \[\Rightarrow \] \[2r=a+b-c\] Now, \[2r+27R=a+b-c+c\] \[\Rightarrow \] \[2(r+R)=a+b\]You need to login to perform this action.
You will be redirected in
3 sec