A) + 3 to + 6
B) + 6 to + 3
C) + 6 to + 2
D) remains unchanged
Correct Answer: B
Solution :
The reaction of acidic\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]with\[{{H}_{2}}S\]is as \[\underset{O.N.=+6}{\mathop{C{{r}_{2}}O_{7}^{2-}}}\,+14{{H}^{+}}+3{{S}^{2-}}\xrightarrow[{}]{{}}\underset{O.N.=+3}{\mathop{2C{{r}^{3+}}}}\,\] \[+3S+7{{H}_{2}}O\] Hence, the oxidation number of Cr changes + 6 to +3.You need to login to perform this action.
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