A) 0.2
B) 0.4
C) 0.6
D) 0.8
Correct Answer: C
Solution :
According to Raoult's law, lowering of vapour pressure ocmole fraction of solute. \[\frac{10\,mm}{20\,mm}=\frac{0.2}{X}\] \[X=\frac{0.2\times 20}{10}=0.4\] Here, \[X=\]mole fraction of solute \[\therefore \]mole fraction of solvent \[=1-0.4\] \[=0.6\]You need to login to perform this action.
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