A) 2.76
B) 3.76
C) 4.76
D) 0.76
Correct Answer: C
Solution :
10 mL \[1.0\,M\,C{{H}_{3}}COOH\equiv 10N\,C{{H}_{3}}COOH\] 20 mL\[0.5M\,C{{H}_{3}}COONa\equiv 10\,N\,C{{H}_{3}}COONa\] \[pH=p{{K}_{a}}+\log \frac{[Salt]}{[Acid]}\] \[=4.76+\log \frac{[10]}{[10]}\] \[=4.76\]You need to login to perform this action.
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