A) 0
B) 1
C) \[-1\]
D) None of these
Correct Answer: C
Solution :
Given, equation is \[({{a}^{2}}+4a+3){{x}^{2}}+({{a}^{2}}-a-2)x+a(a+1)=0\] Let\[a=-1,\]then \[0.{{x}^{2}}+0.x-1(-1+1)=0\] \[\Rightarrow \] \[0=0\] Hence, option [c] is correct.You need to login to perform this action.
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