A) 11.2 L
B) 22.4 L
C) 8.4 L
D) 7.4 L
Correct Answer: C
Solution :
\[\underset{\begin{smallmatrix} 2\times 78 \\ =156g \end{smallmatrix}}{\mathop{2{{C}_{6}}{{H}_{6}}}}\,+\underset{\begin{smallmatrix} 15\times 22.4 \\ =336\,L \end{smallmatrix}}{\mathop{15{{O}_{2}}}}\,\xrightarrow{{}}12C{{O}_{2}}+6{{H}_{2}}O\] \[\because \]\[{{O}_{2}}\]required in the combustion of 156 g liquid benzene = 336 L \[\therefore \]\[{{O}_{2}}\]required in the combustion of 3.9 g liquid benzene \[=\frac{366\times 3.9}{156}=8.4\,L\]You need to login to perform this action.
You will be redirected in
3 sec