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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2008

  • question_answer
    The combustion of liquid benzene in oxygen is as \[2{{C}_{6}}{{H}_{6}}+15{{O}_{2}}\xrightarrow[{}]{{}}12C{{O}_{2}}+6{{H}_{2}}O\] How many litre of oxygen will require on complete combustion of 3.9 g liquid benzene at STP

    A)  11.2 L             

    B)  22.4 L

    C)  8.4 L              

    D)  7.4 L

    Correct Answer: C

    Solution :

     \[\underset{\begin{smallmatrix}  2\times 78 \\  =156g \end{smallmatrix}}{\mathop{2{{C}_{6}}{{H}_{6}}}}\,+\underset{\begin{smallmatrix}  15\times 22.4 \\  =336\,L \end{smallmatrix}}{\mathop{15{{O}_{2}}}}\,\xrightarrow{{}}12C{{O}_{2}}+6{{H}_{2}}O\] \[\because \]\[{{O}_{2}}\]required in the combustion of 156 g liquid benzene = 336 L \[\therefore \]\[{{O}_{2}}\]required in the combustion of 3.9 g liquid benzene \[=\frac{366\times 3.9}{156}=8.4\,L\]


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