question_answer

Which of the following transition gives the photon of minimum frequency?

A)  n = 2 to n = 1      

B)  n = 3 to n = 1

C)  n = 3 to n = 2     

D)  n = 4 to n = 3

Correct Answer: A

Solution :

  \[{{E}_{1}}=-13.6-(-3.4)=-10.2eV\] \[{{E}_{2}}=-13.6-(-1.51)=-12.9eV\] \[{{E}_{3}}=-3.4-(-1.5)=-1.89eV\] \[{{E}_{4}}=-1.51-(-0.85)=-0.66eV\] \[{{E}_{4}}\]is least ie, frequency is lowest.