A) \[-1\]
B) 0
C) \[1\]
D) 2
Correct Answer: C
Solution :
\[\underset{x\to 1}{\mathop{\lim }}\,\frac{2x-f(x)}{x-1}\] \[=\underset{x\to 1}{\mathop{\lim }}\,\frac{2-f'(x)}{1}\] [by L' Hospital rule] \[=2-f'(1)=2-(1)=1\]You need to login to perform this action.
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