A) \[{{x}^{2}}+{{y}^{2}}-4y+3=0\]
B) \[{{x}^{2}}+{{y}^{2}}-2y-2=0\]
C) \[{{x}^{2}}+{{y}^{2}}-2x-27+2=0\]
D) \[{{x}^{2}}+{{y}^{2}}-2x-2y+1=0\]
Correct Answer: B
Solution :
Since, circle touches the x-axis and y-axis at points (1,0) and (0,1) respectively. So, centre of circle is (1,1) and radius is 1. Hence, equation of circle is \[{{(x-1)}^{2}}+{{(y-1)}^{2}}={{1}^{2}}\] \[\Rightarrow \] \[{{x}^{2}}+{{y}^{2}}-2x-2y+1=0\]You need to login to perform this action.
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