A) \[-1\]
B) \[-\frac{1}{2}\]
C) \[1\]
D) \[\frac{1}{2}\]
Correct Answer: B
Solution :
Since roots of the equation \[{{x}^{2}}+2(k+1)x+{{k}^{2}}=0\] are equal. \[\therefore \] \[{{B}^{2}}=4AC\] \[\Rightarrow \] \[4{{(k+1)}^{2}}=4{{k}^{2}}\] \[\Rightarrow \] \[4{{k}^{2}}+4+8k=4{{k}^{2}}\] \[\Rightarrow \] \[k=-\frac{1}{2}\]You need to login to perform this action.
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