A) \[\left( -\frac{2}{3},4 \right)\]
B) \[\left( \frac{-2}{3},\infty \right)\]
C) (0,1)
D) None of these
Correct Answer: A
Solution :
\[|x+3|>|2x-1|\] \[\Rightarrow \] \[|x+3{{|}^{2}}>|2x-1{{|}^{2}}\] \[\Rightarrow \] \[{{x}^{2}}+9+6x>4{{x}^{2}}+1-4x\] \[\Rightarrow \] \[3{{x}^{2}}-10x-8<0\] \[\Rightarrow \] \[(x-4)(3x+2)<0\]You need to login to perform this action.
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