A) \[{{10}^{5}}Hz\]
B) 10 Hz
C) \[\frac{{{10}^{5}}}{2\pi }Hz\]
D) \[\frac{10}{2\pi }Hz\]
Correct Answer: A
Solution :
Frequency, \[v=\frac{1}{2\pi \sqrt{LC}}\] \[=\frac{I}{2\pi \sqrt{{{10}^{-6}}\times {{10}^{-4}}}}=\frac{{{10}^{5}}}{2\pi }Hz\]You need to login to perform this action.
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