A) 1
B) 2
C) 3
D) 4
Correct Answer: A
Solution :
The two half-reactions for the given reaction are \[2N{{H}_{3}}\xrightarrow[{}]{{}}{{N}_{2}}{{H}_{4}}+2{{H}^{+}}+2{{e}^{-}}\] \[OC{{l}^{-}}+2{{H}^{+}}+2{{e}^{-}}\xrightarrow[{}]{{}}C{{l}^{-}}+{{H}_{2}}O\] On adding both the reactions, we get \[2N{{H}_{3}}+OC{{l}^{-}}\xrightarrow[{}]{{}}{{N}_{2}}{{H}_{4}}+C{{l}^{-}}+{{H}_{2}}O\] The obtained equation is a balanced equation and in it, the coefficient of\[{{N}_{2}}{{H}_{4}}\]is 1.You need to login to perform this action.
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