A) Q
B) \[Q/2\]
C) \[-Q/2\]
D) \[-Q\]
Correct Answer: C
Solution :
The total force on Q \[\frac{Qq}{4\pi {{\varepsilon }_{0}}{{\left( \frac{1}{2} \right)}^{2}}}+\frac{4{{Q}^{2}}}{4\pi {{\varepsilon }_{0}}{{l}^{2}}}=0\] \[\Rightarrow \] \[\frac{Qp}{4\pi {{\varepsilon }_{0}}{{\left( \frac{1}{2} \right)}^{2}}}=-\frac{4{{Q}^{2}}}{4\pi {{\varepsilon }_{0}}{{l}^{2}}}\] \[\Rightarrow \] \[q=-Q\]You need to login to perform this action.
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